Question

Токарь за час изготавливает 90 деталей а ученик за 60 только приступил к работе через 2 часа после того как начал работу ученик За какое время он догонит ученика по количество изготовленных деталей

Answer 1

Обозначим за х время, которое нужно мастеру. Тогда ученик затратит (х+2) часа. Производительность мастера 90 д/ч, ученика 60 д/ч. Поскольку в результате должно получиться равное количество деталей, составляем уравнение:
60*(2+х)=90х
120+60х=90х
120=30х
х=4
Через 4 часа мастер догонит ученика.

Answer 2

Problem Analysis

We are given that a skilled worker can produce 90 parts in one hour, while an apprentice who started working 2 hours later can produce 60 parts in one hour. We need to determine how long it will take for the apprentice to catch up to the skilled worker in terms of the number of parts produced.

Solution

Let's assume that it takes the apprentice x hours to catch up to the skilled worker. In that case, the skilled worker would have been working for x + 2 hours.

We can set up the following equation to represent the situation:

90 * (x + 2) = 60 * x

Simplifying the equation:

90x + 180 = 60x

Subtracting 60x from both sides:

30x + 180 = 0

Subtracting 180 from both sides:

30x = -180

Dividing both sides by 30:

x = -6

Since time cannot be negative, we can conclude that the apprentice will never catch up to the skilled worker in terms of the number of parts produced.

Answer

The apprentice will never catch up to the skilled worker in terms of the number of parts produced.