Question

Из двух поселков ,расстояние между которыми 22км,навстречу друг другу вышли 2 пешехода.Первый из них вышел на 1ч раньше второго.Они встретились через 2 часа после того как вышел второй пешеход,скорость которого на 1км/ч больше,чем скорость первого.Какова скорость второго пешехода?

Answer 1

22:2=11-км/ч на двоих 11-1=10-км/ч если у одного на 1 км/ч быстрее 10:2=5 км/ч- скорость 1 5+1=6- км /ч-скорость 2

Answer 2

Problem Analysis

We are given two pedestrians who start walking towards each other from two different villages. The distance between the villages is 22 km. The first pedestrian starts 1 hour earlier than the second pedestrian. They meet after 2 hours from the time the second pedestrian starts walking. The second pedestrian's speed is 1 km/h faster than the first pedestrian's speed. We need to find the speed of the second pedestrian.

Solution

Let's assume the speed of the first pedestrian is x km/h. Therefore, the speed of the second pedestrian is x + 1 km/h.

We can use the formula distance = speed × time to solve this problem.

The distance covered by the first pedestrian in 2 hours is 2x km.

The distance covered by the second pedestrian in 2 hours is (x + 1) × 2 km.

Since they are walking towards each other, the sum of the distances covered by both pedestrians should be equal to the total distance between the villages, which is 22 km.

Therefore, we can write the equation:

2x + 2(x + 1) = 22

Simplifying the equation:

2x + 2x + 2 = 22

4x + 2 = 22

4x = 20

x = 5

The speed of the second pedestrian is x + 1 = 5 + 1 = 6 km/h.

Answer

The speed of the second pedestrian is 6 km/h.