
Меньшее основание равнобедренной трапеции равно боковой стороне. Высота равна 8 см, периметр-52см,
а площадь -128 см кв, надите длины сторон трапеции

Ответы на вопрос

S=128.по ф-ле S=(BC+AD)÷2·H=128⇒BC+AD=32⇒BC=32-AD.
P=AB+BC+CD+AD=3BC+AD=52⇒3(32-AD)+AD=52⇒AD=22⇒BC=10
Ответ Стороны трапеции равны 22 и 10



Given Information:
We are given the following information about a trapezoid: - The smaller base is equal to one of the lateral sides. - The height is 8 cm. - The perimeter is 52 cm. - The area is 128 cm².Solution:
To find the lengths of the sides of the trapezoid, we can use the formulas for the perimeter and area of a trapezoid.Let's denote the lengths of the sides of the trapezoid as follows: - The smaller base: x - The larger base: y - The two lateral sides: a and b
The perimeter of a trapezoid is given by the formula: Perimeter = x + y + a + b
We are given that the perimeter is 52 cm, so we can write the equation: x + y + a + b = 52 The area of a trapezoid is given by the formula: Area = (x + y) * height / 2
We are given that the area is 128 cm² and the height is 8 cm, so we can write the equation: (x + y) * 8 / 2 = 128
Simplifying this equation, we get: x + y = 32 We also know that the smaller base is equal to one of the lateral sides, so we can write the equation: x = a Now we have a system of equations: 1. x + y + a + b = 52 2. x + y = 32 3. x = a
We can solve this system of equations to find the values of x, y, a, and b.
Substituting equation 3 into equation 2, we get: a + y = 32
Substituting equation 3 into equation 1, we get: 2x + y + b = 52
Now we have a new system of equations: 1. a + y = 32 2. 2x + y + b = 52 3. x = a
Substituting equation 3 into equation 1, we get: x + y = 32
Now we have a new system of equations: 1. x + y = 32 2. 2x + y + b = 52 3. x = a
Solving this system of equations, we find: x = 8 y = 24 a = 8 b = 12
Therefore, the lengths of the sides of the trapezoid are: - The smaller base: 8 cm - The larger base: 24 cm - The two lateral sides: 8 cm and 12 cm


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