Question

как решить задачу:два самолета летели с одинаковой средней скоростью .Первый самолет был в воздухе 4 часа ,второй 6 часов .первый самолет пролетел меньше второго на 1400 км . какое расстояние пролетел каждый самолет

Answer 1

1) 6 - 4 = 2 часа - был больше второй самолёт, чем первый

2) 1400 : 2 = 700 км/час - скорость самолёта

3) 700 * 4 = 2800 км - пролетел первый самолёт

4) 700 * 6 = 4200 км - пролетел второй самолёт

Answer 2

Problem Analysis

We have two airplanes flying at the same average speed. The first airplane is in the air for 4 hours, while the second airplane is in the air for 6 hours. The first airplane flies 1400 km less than the second airplane. We need to find the distance traveled by each airplane.

Solution

Let's assume the distance traveled by the first airplane is x km. Since the second airplane flies 1400 km more, the distance traveled by the second airplane is x + 1400 km.

We know that speed is equal to distance divided by time. Since both airplanes have the same average speed, we can set up the following equation:

x / 4 = (x + 1400) / 6

To solve this equation, we can cross-multiply:

6x = 4(x + 1400)

Simplifying the equation:

6x = 4x + 5600

2x = 5600

x = 2800

Therefore, the first airplane traveled 2800 km, and the second airplane traveled 2800 + 1400 = 4200 km.

Answer

The first airplane traveled 2800 km, and the second airplane traveled 4200 km.