Question

X^2-16=0 2) x2-24=-5x 3) 5x2+5x-15=2x^2+11x+9 помогите решить

Answer 1

1) x=-4 ; 4
2) x=-8 ; 3
3) x=-2 ; 4

Answer 2

Sure, I can help you solve these equations!

1. $x^2 - 16 = 0$ This is a difference of squares, and you can factor it as $(x - 4)(x + 4) = 0$. So, the solutions are $x = 4$ and $x = -4$.

2. $x^2 - 24 = -5x$ Rearrange the equation to get $x^2 + 5x - 24 = 0$, and then factor it as $(x + 8)(x - 3) = 0$. So, the solutions are $x = -8$ and $x = 3$.

3. $5x^2 + 5x - 15 = 2x^2 + 11x + 9$ Move all terms to one side to set the equation to zero: $3x^2 - 6x - 24 = 0$. Factor out the common factor, giving you $3(x^2 - 2x - 8) = 0$. Then, factor the quadratic as $(x - 4)(x + 2) = 0$. So, the solutions are $x = 4$ and $x = -2$.

Hope that helps! If you have any questions about the steps, feel free to ask.