Question

1)x+ 1\2x+1 1\2=3 2) 4 6\19x+ 9 15\19x-2\19x+x- 5 1\19= 230 1\19

Answer 1

Если во 2 пробелы это × то правильно
1)3,6
2)1,34

Answer 2

It seems like you have two equations that you'd like to solve for the variable "x." Let's work on each equation separately.

1. $x + \frac{1}{2}x + \frac{1}{2} = 3$

To solve this equation, you can combine like terms on the left side:

$\frac{3}{2}x + \frac{1}{2} = 3$

Next, isolate the variable "x" by subtracting $\frac{1}{2}$ from both sides:

$\frac{3}{2}x = 3 - \frac{1}{2}$

Now, simplify the right side:

$\frac{3}{2}x = \frac{6}{2} - \frac{1}{2} = \frac{5}{2}$

Finally, divide both sides by $\frac{3}{2}$ to solve for "x":

$x = \frac{\frac{5}{2}}{\frac{3}{2}} = \frac{5}{2} \times \frac{2}{3} = \frac{5}{3}$

So, the solution to the first equation is $x = \frac{5}{3}$.

2. $4\frac{6}{19}x + \frac{9}{15}\frac{19}{19}x - \frac{2}{19}x + x - \frac{5}{1}\frac{19}{19} = 230\frac{1}{19}$

First, simplify the fractions:

$4\frac{6}{19}x + \frac{9}{15}\frac{19}{19}x - \frac{2}{19}x + x - \frac{5}{1}\frac{19}{19} = 230\frac{1}{19}$

$4\frac{6}{19}x + \frac{9}{15}x - \frac{2}{19}x + x - 5\frac{19}{19} = 230\frac{1}{19}$

Now, work on each term separately:

$4\frac{6}{19}x$ can be simplified to $\frac{76}{19}x$.

$\frac{9}{15}x$ can be simplified to $\frac{3}{5}x$.

$-\frac{2}{19}x$ remains the same.

$5\frac{19}{19}$ simplifies to just $5$.

Now, rewrite the equation with the simplified terms:

$\frac{76}{19}x + \frac{3}{5}x - \frac{2}{19}x + x - 5 = 230\frac{1}{19}$