Question

34÷х-3=31 (х-5)×4=36 3х+х=8 7+х:7=8

Answer 1

34÷х-3=31

34:х=31+3

34:х=34

х=34:34

х=1

(х-5)×4=36

х-5=36:4

х-5=9

х=9+5

х=14

3х+х=8

4х=8

х=8:4

х=2

7+х:7=8

х:7=8-7

х:7=1

х=7*1

х=7

Answer 2

1.34:х-3=31                      

34:х=31+3

34:х=34

х=1

2.4х-20=36

4х=56

х=14

3.4х=8

х=2

4.х:7=1

х=7

Answer 3

Let's solve each of these equations step by step:

1. 34÷x - 3 = 31

   First, add 3 to both sides of the equation to isolate the fraction:

   34÷x - 3 + 3 = 31 + 3 34÷x = 34

   Now, multiply both sides of the equation by x to solve for x:

   x * (34÷x) = 34 * x 34 = 34x

   Finally, divide both sides by 34 to find the value of x:

   x = 34/34 x = 1

2. (x - 5) × 4 = 36

   First, divide both sides by 4:

   (x - 5) × 4 ÷ 4 = 36 ÷ 4 x - 5 = 9

   Now, add 5 to both sides of the equation to solve for x:

   x - 5 + 5 = 9 + 5 x = 14

3. 3x + x = 8

   Combine like terms on the left side of the equation:

   3x + x = 4x

   Now, set the equation equal to 8:

   4x = 8

   Finally, divide both sides by 4 to solve for x:

   4x / 4 = 8 / 4 x = 2

4. 7 + x/7 = 8

   First, subtract 7 from both sides of the equation:

   7 + x/7 - 7 = 8 - 7 x/7 = 1

   Now, multiply both sides by 7 to solve for x:

   (x/7) * 7 = 1 * 7 x = 7

So, the solutions for each equation are:

1. x = 1
2. x = 14
3. x = 2
4. x = 7

Answer 4

Let's solve each of these equations step by step:

1. $\frac{34}{x} - 3 = 31$:

First, add 3 to both sides of the equation: $\frac{34}{x} = 31 + 3$ $\frac{34}{x} = 34$

Now, multiply both sides by $x$ to isolate $x$: $x \cdot \frac{34}{x} = 34 \cdot x$ $34 = 34x$

Divide both sides by 34 to find the value of $x$: $x = \frac{34}{34}$ $x = 1$

So, $x = 1$ is the solution to the first equation.

2. $(x-5) \times 4 = 36$:

First, divide both sides by 4: $\frac{(x-5) \times 4}{4} = \frac{36}{4}$ $x - 5 = 9$

Now, add 5 to both sides of the equation to isolate $x$: $x - 5 + 5 = 9 + 5$ $x = 14$

So, $x = 14$ is the solution to the second equation.

3. $3x + x = 8$:

Combine like terms on the left side: $3x + x = 4x$

Now, set the equation equal to 8: $4x = 8$

Divide both sides by 4 to find the value of $x$: $\frac{4x}{4} = \frac{8}{4}$ $x = 2$

So, $x = 2$ is the solution to the third equation.

4. $7 + \frac{x}{7} = 8$:

First, subtract 7 from both sides of the equation: $\frac{x}{7} = 8 - 7$ $\frac{x}{7} = 1$

Now, multiply both sides by 7 to isolate $x$: $x = 7 \times 1$ $x = 7$

So, $x = 7$ is the solution to the fourth equation.