Question

9 + (53-68:x)=45 хелп

Answer 1

Ответ: 9 + (53-68:x)=45 ⇒53-68/х=45-9=36⇒68/х=53-36=17⇒х=68/17=4.

Ответ: х=4.

Пошаговое объяснение:

Answer 2

To solve this equation, you need to follow the order of operations (PEMDAS/BODMAS), which stands for Parentheses/Brackets, Exponents/Orders (i.e., powers and square roots, etc.), Multiplication and Division (left-to-right), and Addition and Subtraction (left-to-right). In this case, we have parentheses and division, so we should deal with them first.

The equation is:

9 + (53 - 68/x) = 45

First, let's isolate the expression within the parentheses:

53 - 68/x

Now, to isolate x, we can start by subtracting 9 from both sides of the equation:

(53 - 68/x) = 45 - 9

Simplify the right side:

(53 - 68/x) = 36

Next, isolate the term containing x. To do this, we can add 68/x to both sides of the equation:

(53 - 68/x) + 68/x = 36 + 68/x

The 68/x term cancels on the left side:

53 = 36 + 68/x

Now, subtract 36 from both sides to isolate 68/x:

53 - 36 = 68/x

17 = 68/x

Now, to find x, we can solve for it by isolating x on one side. Since 68 is divided by x, you can reciprocate both sides of the equation:

1/x = 17/68

Now, solve for x by taking the reciprocal of both sides:

x = 68/17

Now, simplify the fraction:

x = 4

So, the solution to the equation is x = 4.