Question

Турист проехал на велосипеде 80% пути,а остальной путь он прошел пешком и потратил на путь пешком вдвое больше времени, чем на велосипедную езду. Во сколько раз турист ехал на велосипеде быстрее, чем шел?

Answer 1

Если весь путь взять за100%
100-80=20%шел пешком
80:20=4 
в4раза быстрее ехал,чем шел

Answer 2

Problem Analysis

A tourist traveled 80% of the distance on a bicycle and the remaining distance on foot. The time taken for walking was twice as long as the time taken for cycling. We need to determine how many times faster the tourist traveled on the bicycle compared to walking.

Solution

Let's assume that the total distance traveled by the tourist is D units.

The distance traveled on the bicycle is 80% of the total distance, which is 0.8D units.

The remaining distance traveled on foot is 20% of the total distance, which is 0.2D units.

The time taken for walking is twice as long as the time taken for cycling. Let's assume the time taken for cycling is T units. Therefore, the time taken for walking is 2T units.

To find the speed of the tourist on the bicycle, we can use the formula: Speed = Distance / Time.

The speed of the tourist on the bicycle is 0.8D / T units.

The speed of the tourist on foot is 0.2D / (2T) units.

To find how many times faster the tourist traveled on the bicycle compared to walking, we can divide the speed of the bicycle by the speed of walking: (0.8D / T) / (0.2D / (2T)).

Simplifying this expression, we get: (0.8D / T) * (2T / 0.2D) = 4.

Therefore, the tourist traveled on the bicycle 4 times faster than walking.

Answer

The tourist traveled on the bicycle 4 times faster than walking.