
(1425:75+32)×(2346:51-39)-354= (784:86+12)×(5152:92-48)-439 помогите


Ответы на вопрос

[1425;75+32]x[2346;51-39]-354=[19+32]x[46-39]-354=[51x7]-354=357-354=3
[784;86+12]x[5152;92-48]-439
784;86 не делится



Calculating the Expression
To solve the given expression (1425:75 + 32) × (2346:51 - 39) - 354 = (784:86 + 12) × (5152:92 - 48) - 439, we can follow the order of operations (parentheses, exponents, multiplication and division from left to right, and addition and subtraction from left to right).First, let's solve the expressions within the parentheses:
1. (1425:75 + 32): - The result of 1425 divided by 75 plus 32.
2. (2346:51 - 39): - The result of 2346 divided by 51 minus 39.
3. (784:86 + 12): - The result of 784 divided by 86 plus 12.
4. (5152:92 - 48): - The result of 5152 divided by 92 minus 48.
Let's calculate each of these expressions step by step.
Calculating the Expressions within the Parentheses
1. (1425:75 + 32): - 1425 divided by 75 equals 19, and then adding 32 gives us 51.2. (2346:51 - 39): - 2346 divided by 51 equals 46, and then subtracting 39 gives us 7.
3. (784:86 + 12): - 784 divided by 86 equals 9, and then adding 12 gives us 21.
4. (5152:92 - 48): - 5152 divided by 92 equals 56, and then subtracting 48 gives us 8.
Now that we have the values for the expressions within the parentheses, we can proceed to calculate the entire expression.
Calculating the Entire Expression
Substituting the values we found into the original expression, we get:(51) × (7) - 354 = (21) × (8) - 439
Now, let's calculate the values on both sides of the equation.
1. Left-hand side: - 51 multiplied by 7 equals 357. - Subtracting 354 from 357 gives us 3.
2. Right-hand side: - 21 multiplied by 8 equals 168. - Subtracting 439 from 168 gives us -271.
Final Result
After evaluating the entire expression, we find that the result is: 3 = -271It seems there might be an error in the given expression, as the left-hand side and the right-hand side do not equal each other. If there was a mistake in the input, please provide the correct expression, and I'd be happy to help further!


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