Question

8^2/3 - (1/2)^4 + 3^0

Answer 1

Ответ:

Пошаговое объяснение:

Answer 2

Let's break down the expression step by step:

1. $8^2/3$: $\frac{8^2}{3} = \frac{64}{3}$

2. $(1/2)^4$: $\left(\frac{1}{2}\right)^4 = \frac{1}{2^4} = \frac{1}{16}$

3. $3^0$: Any number raised to the power of 0 is 1, so $3^0 = 1$.

Now, substitute these values back into the original expression:

$\frac{64}{3} - \frac{1}{16} + 1$

To combine the fractions, find a common denominator, which in this case is 48:

$\frac{64 \times 16}{3 \times 16} - \frac{1 \times 3}{16 \times 3} + \frac{48}{16}$

$\frac{1024}{48} - \frac{3}{48} + \frac{48}{16}$

Now, combine the fractions:

$\frac{1024 - 3 + 144}{48}$

$\frac{1165}{48}$

So, the simplified result is $\frac{1165}{48}$.