Question

8×4+27:9×8:6+5×5-21:7×4=

Answer 1

$8*4+27:9*8:6+5*5-21:7*4=49\\1) 8*4=32\\2) 27:9=3\\3) 8:6=1\frac{1}{3} \\4)5*5=25\\5) 21:7=3\\6) 3*1\frac{1}{3} =3*\frac{1+1*3}{3}=3+\frac{4}{3}=\frac{3*4}{4} =\frac{12}{3} =4\\ 7) 3*4=12\\8) 32+4=36\\9) 36+25=61\\10) 61-12=49$

Answer 2

Ответ:

$8\cdot 4+27:9\cdot 8:6+5\cdot 5-21:7\cdot 4=32+\dfrac{27}{9}\cdot \dfrac{8}{6}+25-\dfrac{21}{7}\cdot 4=\\\\=32+3\cdot \dfrac{4}{3}+25-3\cdot 4=32+4+25-12=49$

Answer 3

To solve this expression, you should follow the order of operations (PEMDAS/BODMAS), which stands for Parentheses/Brackets, Exponents/Orders (i.e., powers and square roots, etc.), Multiplication and Division (left-to-right), and Addition and Subtraction (left-to-right).

Let's break it down step by step:

1. Start with multiplication and division from left to right: 8 × 4 = 32 27 ÷ 9 = 3 8 ÷ 6 = 4 5 × 5 = 25 21 ÷ 7 = 3 4 × 3 = 12

2. Now, we have: 32 + 3 + 4 + 25 - 3 + 12

3. Perform addition and subtraction from left to right: 32 + 3 = 35 35 + 4 = 39 39 + 25 = 64 64 - 3 = 61 61 + 12 = 73

So, the value of the expression is 73.