Question

Два поезда одновременно отправились от одной станции в противоположных направлениях.через 2ч расстояние между ними стало 280км.с какой средней скоростью двигался каждый поезд,если у первого поезда она была на 20км больше,чем у второго

Answer 1

280-2÷2=278 ответ :279бльше чем у другово

Answer 2

Problem Analysis

We have two trains that start from the same station and travel in opposite directions. After 2 hours, the distance between them is 280 km. The first train is traveling 20 km/h faster than the second train. We need to find the average speed of each train.

Solution

Let's assume the speed of the second train is x km/h. Since the first train is traveling 20 km/h faster, its speed will be x + 20 km/h.

We know that speed = distance / time. After 2 hours, the distance between the trains is 280 km. Using this information, we can set up the following equation:

2(x + x + 20) = 280

Simplifying the equation:

4x + 40 = 280

4x = 240

x = 60

Therefore, the speed of the second train is 60 km/h, and the speed of the first train is 60 + 20 = 80 km/h.

Answer

The second train was traveling at an average speed of 60 km/h, while the first train was traveling at an average speed of 80 km/h.

Explanation

The problem states that the two trains started from the same station and traveled in opposite directions. After 2 hours, the distance between them was 280 km. The first train was traveling 20 km/h faster than the second train.

To find the average speed of each train, we can use the formula speed = distance / time. After 2 hours, the distance between the trains is 280 km. Let's assume the speed of the second train is x km/h. Since the first train is traveling 20 km/h faster, its speed will be x + 20 km/h.

Using the formula, we can set up the equation 2(x + x + 20) = 280. Simplifying this equation, we get 4x + 40 = 280. Solving for x, we find that x = 60.

Therefore, the speed of the second train is 60 km/h, and the speed of the first train is 60 + 20 = 80 km/h.