Question

1) (х-1)²=12) (х+3)²-9=03) (х-5)²+16=04) (2х-1)²-100=0​

Answer 1

Ответ:

Це правильна відповідь

Answer 2

Let's solve each of these quadratic equations step by step:

1. (x - 1)² = 1

To solve this equation, take the square root of both sides:

x - 1 = ±1

Now, add 1 to both sides:

x = 1 ± 1

So, the solutions are: x = 1 + 1 = 2 x = 1 - 1 = 0

2. (x + 3)² - 9 = 0

First, add 9 to both sides of the equation:

(x + 3)² = 9

Now, take the square root of both sides:

x + 3 = ±3

Subtract 3 from both sides:

x = 3 ± 3

So, the solutions are: x = 3 + 3 = 6 x = 3 - 3 = 0

3. (x - 5)² + 16 = 0

Subtract 16 from both sides:

(x - 5)² = -16

Since a square cannot be negative, there are no real solutions to this equation.

4. (2x - 1)² - 100 = 0

First, add 100 to both sides:

(2x - 1)² = 100

Take the square root of both sides:

2x - 1 = ±10

Add 1 to both sides:

2x = 1 ± 10

Now, divide by 2:

x = (1 ± 10) / 2

So, the solutions are: x = (1 + 10) / 2 = 11 / 2 = 5.5 x = (1 - 10) / 2 = -9 / 2 = -4.5

The solutions to each equation are as follows:

1. x = 2 and x = 0
2. x = 6 and x = 0
3. No real solutions
4. x = 5.5 and x = -4.5