Question

(х-5)^2+5(2х-1)=0 ?????​

Answer 1

х²-10х+25+10х-5=0

х²+20=0

х²= -20

нет корней

Answer 2

To solve the equation $(x - 5)^2 + 5(2x - 1) = 0$, you can follow these steps:

1. Expand and simplify the equation: $(x - 5)^2 + 5(2x - 1) = 0$ $(x^2 - 10x + 25) + (10x - 5) = 0$

2. Combine like terms: $x^2 - 10x + 25 + 10x - 5 = 0$

3. Simplify further: $x^2 + 20 = 0$

4. Subtract 20 from both sides to isolate the $x^2$ term: $x^2 = -20$

5. Take the square root of both sides. Remember that when you take the square root of a negative number, you get a complex solution: $x = ±√(-20)$

6. Simplify the complex square root: $x = ±√(20i)$

So, the solutions to the equation are complex numbers:

$x = √(20i)$ or $x = -√(20i)$

These solutions involve the imaginary unit $i$, indicating that they are complex numbers.