Question

1. 6 - а = 3.(3а -8) 2. 8x - (2x +4) = 2·(3x - 2)​

Answer 1

Ответ:

Пошаговое объяснение:

6 - а = 3(3а - 8)

6 - а = 9а - 24

-а - 9а = -24 - 6

-10а = -30

а = -30 : (-10)

а = 3

8х - (2х + 4) = 2(3х - 2)

8х - 2х - 4 = 6х - 4

6х - 4 = 6х - 4

Утверждение верно для любого значения х, так как обе части одинаковые

х € R

Answer 2

Let's solve these equations step by step:

1. $6 - a = 3(3a - 8)$

First, distribute the 3 on the right side of the equation:

$6 - a = 9a - 24$

Now, let's isolate the variable $a$ on one side of the equation. Add $a$ to both sides of the equation to get all the $a$ terms on the left side:

$6 - a + a = 9a - 24 + a$

The $a$ term on the left cancels out:

$6 = 9a - 24$

Now, add 24 to both sides to isolate the $9a$ term:

$6 + 24 = 9a$

$30 = 9a$

Finally, divide both sides by 9 to solve for $a$:

$a = \frac{30}{9}$

Simplify the fraction:

$a = \frac{10}{3}$

So, the solution to the first equation is $a = \frac{10}{3}$.

2. $8x - (2x + 4) = 2(3x - 2)$

First, distribute the 2 on the right side of the equation:

$8x - 2x - 4 = 6x - 4$

Now, combine like terms on both sides of the equation. Subtract $6x$ from both sides:

$8x - 2x - 6x - 4 = -4$

Simplify:

$0x - 4 = -4$

Now, we have:

$-4 = -4$

This equation is true for any value of $x$. So, there is no unique solution for $x$, and it is called an identity. In other words, $x$ can be any real number, and the equation will still be satisfied.

So, the solution to the second equation is that it is true for all real numbers $x$.