Question

9), [0,3x + 0,2y + 0,9 = 0, 1-3x - 2y = 9;​

Answer 1

Пошаговое объяснение:

я не знаю

Я не знаю я не знаю я не знаю я не знаю я не знаю я не знаю

Answer 2

It seems like you have a system of two linear equations:

1. 0.3x + 0.2y + 0.9 = 0
2. 1 - 3x - 2y = 9

You can solve this system of equations using the method of substitution or elimination. Let's use the elimination method in this case.

First, let's rewrite both equations to make them easier to work with:

1. 0.3x + 0.2y = -0.9
2. -3x - 2y = 9 - 1

Now, we can multiply both sides of equation 2 by -1 to make the coefficients of y's in both equations cancel each other out:

1. 0.3x + 0.2y = -0.9
2. 3x + 2y = -8

Now, we can add equation 1 and equation 2 together to eliminate the y variable:

(0.3x + 0.2y) + (3x + 2y) = (-0.9) + (-8)

Combine like terms:

3.3x + 0 = -8.9

Now, subtract 0 from both sides:

3.3x = -8.9

Divide both sides by 3.3 to isolate x:

x = -8.9 / 3.3

Now, you can calculate the value of x:

x ≈ -2.697

Now that you have the value of x, you can substitute it back into either equation 1 or 2 to solve for y. Let's use equation 1:

0.3x + 0.2y = -0.9

0.3(-2.697) + 0.2y = -0.9

-0.8091 + 0.2y = -0.9

Now, add 0.8091 to both sides to isolate y:

0.2y = -0.9 + 0.8091

0.2y ≈ -0.0909

Now, divide both sides by 0.2 to find y:

y ≈ -0.0909 / 0.2

y ≈ -0.4545

So, the solution to the system of equations is approximately:

x ≈ -2.697 y ≈ -0.4545