Question

(11-х)(22-(11-х)) Решите элементарное уравнение

Answer 1

(11-х)(22-(11-х))=0   
(11-х)(22-11+х)=0   
(11-х)(11+х)=0   
11-х=0; х₁=11.   
11+х=0; х₂=-11.

Answer 2

To solve the elementary equation (11 - x)(22 - (11 - x)) = 0, we need to find the values of x that make the equation true. To do that, we set each factor equal to zero and solve for x:

1. Set (11 - x) = 0: 11 - x = 0 Subtract 11 from both sides: -x = -11 Divide by -1 (which is the same as multiplying both sides by -1): x = 11

2. Set (22 - (11 - x)) = 0: 22 - (11 - x) = 0 Remove the parentheses by distributing the negative sign inside: 22 - 11 + x = 0 Combine like terms: x + 11 = 0 Subtract 11 from both sides: x = -11

So, the solutions to the equation are x = 11 and x = -11.