Question

3,4+2y=7 (y-2,3), 4 (5x+2)=10 (2x-3)÷15 решите

Answer 1

3,4+2y=7(y-2,3)
3,4+2y=7y-16,1
2y-7y=-16,1-3,4
-5y=-19,5
y=-3,9
4(5x+2)=10
20x+8=10
20x=12
x=0,6
(2x-3):15 2x-3_15 *_ дробь

Answer 2

To solve the given equations, let's start with the first one:

1. 3 + 4 + 2y = 7(y - 2) + 3 * 4

Simplify the equation:

3 + 2y = 7y - 14 + 12

Combine like terms:

2y - 7y = 12 - 3 - 14

-5y = -5

Divide by -5 to solve for y:

y = -5 / -5

y = 1

Now, let's move on to the second equation:

2. 4(5x + 2) = 10(2x - 3) ÷ 15

First, solve the expression on the right side of the equation:

10(2x - 3) ÷ 15

= (10 * 2x - 10 * 3) ÷ 15

= (20x - 30) ÷ 15

= 20x / 15 - 30 / 15

= (4/3)x - 2

Now, substitute this back into the equation:

4(5x + 2) = (4/3)x - 2

Distribute on the left side:

20x + 8 = (4/3)x - 2

To solve for x, we need to get all the x terms on one side and the constant terms on the other side:

20x - (4/3)x = -2 - 8

(60x - 4x) / 3 = -10

56x / 3 = -10

Now, multiply both sides by 3 to isolate x:

56x = -30

Finally, divide both sides by 56 to find the value of x:

x = -30 / 56

x ≈ -0.536

So, the solutions to the equations are:

y = 1 x ≈ -0.536