Question

-2•(3-2x)(2x+3)=4+(2x+1)^2

Answer 1

-2(6x+9-4x^2-6x)=4+(4x^2+4x+1)
-2(-4x^2+9)=4+4x^2+4x+1
8x^2-18=4x^2+4x+5
4x^2-4x-23=0
D=16+368=384>0
x1,2=(4 $б$8√6)/(2*4)=(4 $б$8√6)/8=0,5 $б$√6
по-братски дай лучший ответ

Answer 2

To solve the equation -2•(3-2x)(2x+3) = 4 + (2x+1)^2, follow these steps:

Step 1: Expand both sides of the equation Step 2: Simplify the equation Step 3: Solve for x

Let's start with Step 1:

-2•(3-2x)(2x+3) = 4 + (2x+1)^2

Expanding the left side: -2•(6x - 2x^2 + 9 - 6x) = 4 + (4x^2 + 4x + 1)

Simplifying the equation further:

-2•(-2x^2 + 9) = 4 + 4x^2 + 4x + 1

Distribute the -2 on the left side: 4x^2 - 18 = 4 + 4x^2 + 4x + 1

Step 2: Now, combine like terms on the right side:

4x^2 - 18 = 4x^2 + 4x + 5

Step 3: Next, bring all terms to one side of the equation:

4x^2 - 4x^2 - 4x - 5 - 18 = 0

Simplify:

-4x - 23 = 0

Now, solve for x:

-4x = 23

x = -23/4

So, the solution to the equation is x = -23/4.