Question

500гр 20%раствор вещества добавили 300гр 30%раствора этого же вещества какова канцентрация

Answer 1

В 500гр - 100гр чистого вещ

В 300гр - 90гр чистого      | В сумме получается 190гр, по моему так)

Answer 2

To find the concentration of the resulting solution after mixing the two given solutions, you can use the concept of the "mixture" formula. The formula for finding the concentration of a mixture when two solutions are combined is:

C_final = (C1 * V1 + C2 * V2) / (V1 + V2)

Where: C_final = Concentration of the resulting solution C1 = Concentration of the first solution C2 = Concentration of the second solution V1 = Volume of the first solution V2 = Volume of the second solution

Let's apply this formula to the given data:

1. Convert the percentages to decimal form (divide by 100): 20% = 0.20 30% = 0.30

2. Calculate the masses of the solute in each solution: Mass of solute in the first solution = 500g * 0.20 = 100g Mass of solute in the second solution = 300g * 0.30 = 90g

Now, we'll use these calculated masses as the "Volume * Concentration" for each solution.

3. Apply the mixture formula:

C_final = (C1 * V1 + C2 * V2) / (V1 + V2)

C_final = (0.20 * 500g + 0.30 * 300g) / (500g + 300g) C_final = (100g + 90g) / 800g C_final = 190g / 800g

4. Calculate the final concentration:

C_final = 0.2375

Now, convert the concentration back to a percentage:

C_final_percentage = 0.2375 * 100% ≈ 23.75%

So, the concentration of the resulting solution is approximately 23.75%.