Question

9/20×2/3+5/14×7/25; 3. 3/4×2/5-3. 6/25×5/27

Answer 1

Первый пример равен 4/10
Второй пример равен 53/60

Answer 2

Let's solve the expressions step by step:

1. $\frac{9}{20} \times \frac{2}{3} + \frac{5}{14} \times \frac{7}{25}$

Step 1: Calculate the products of the fractions first. $\frac{9}{20} \times \frac{2}{3} = \frac{18}{60}$ (both numerator and denominator are divisible by 2)

$\frac{5}{14} \times \frac{7}{25} = \frac{35}{350}$ (both numerator and denominator are divisible by 5)

Step 2: Add the two results together. $\frac{18}{60} + \frac{35}{350}$

Step 3: Find a common denominator for addition. In this case, the common denominator is 350. $\frac{18}{60} + \frac{35}{350} = \frac{35}{350} + \frac{35}{350}$

Step 4: Add the fractions with the common denominator. $\frac{35}{350} + \frac{35}{350} = \frac{70}{350}$

Step 5: Simplify the fraction. $\frac{70}{350} = \frac{1}{5}$

So, $\frac{9}{20} \times \frac{2}{3} + \frac{5}{14} \times \frac{7}{25} = \frac{1}{5}$

2. $\frac{3}{4} \times \frac{2}{5} - \frac{3}{6} \times \frac{5}{27}$

Step 1: Calculate the products of the fractions first. $\frac{3}{4} \times \frac{2}{5} = \frac{6}{20}$ (both numerator and denominator are divisible by 2)

$\frac{3}{6} \times \frac{5}{27} = \frac{15}{162}$ (both numerator and denominator are divisible by 3)

Step 2: Subtract the second result from the first. $\frac{6}{20} - \frac{15}{162}$

Step 3: Find a common denominator for subtraction. In this case, the common denominator is 162. $\frac{6}{20} - \frac{15}{162} = \frac{486}{1620} - \frac{300}{1620}$

Step 4: Subtract the fractions with the common denominator. $\frac{486}{1620} - \frac{300}{1620} = \frac{186}{1620}$

Step 5: Simplify the fraction. $\frac{186}{1620} = \frac{31}{270}$

So, $\frac{3}{4} \times \frac{2}{5} - \frac{3}{6} \times \frac{5}{27} = \frac{31}{270}$