Question

При каком значении аргумента рав5ны значения функции f(x)=x-3 дробь2 и g(x)=5+2x дробь3

Answer 1

$\frac{x - 3}{2 } = \frac{5 + 2x}{3}$
(х-3)×3=(5+2х)×2
3х-9=10+4х
х=-19

Answer 2

To find the values of x at which the functions f(x) and g(x) are equal, we need to set them equal to each other and solve for x:

f(x) = g(x)

(x - 3) / 2 = (5 + 2x) / 3

To make the equation easier to work with, we can eliminate the fractions by multiplying both sides by 2 * 3 = 6:

6 * (x - 3) = 2 * (5 + 2x)

Now, distribute the multiplication:

6x - 18 = 10 + 4x

Next, bring all the x terms to one side of the equation and the constant terms to the other side:

6x - 4x = 10 + 18

2x = 28

Finally, solve for x:

x = 28 / 2

x = 14

So, the values of x at which the functions f(x) and g(x) are equal are x = 14.