Question

Решите уравнение:2x^+3x+4=0

Answer 1

Ответ:

2x^2+4 всегда больше, чем 3х поэтому нет решений(и дискриминант<0)

Пошаговое объяснение:

Answer 2

To solve the quadratic equation 2x^2 + 3x + 4 = 0, we can use the quadratic formula:

For an equation of the form ax^2 + bx + c = 0, the quadratic formula is given by:

x = (-b ± √(b^2 - 4ac)) / 2a

In our case, a = 2, b = 3, and c = 4. Now, we can plug these values into the formula and calculate the solutions for x:

x = (-(3) ± √((3)^2 - 4(2)(4))) / 2(2) x = (-3 ± √(9 - 32)) / 4 x = (-3 ± √(-23)) / 4

Since the expression under the square root (√(-23)) is negative, this equation has complex solutions. Let's simplify it further:

x = (-3 ± √(23)i) / 4

The solutions for x are:

x = (-3 + √(23)i) / 4 x = (-3 - √(23)i) / 4

Where "i" represents the imaginary unit (√(-1)). These are the two complex solutions to the given quadratic equation.