Question

1/2-1/4 7/12-3/167/16-1/61-1/3​

Answer 1

1)

$\frac{1}{2}^{2} - \frac{1}{4} = \frac{2}{4} - \frac{1}{4} = \frac{1}{4}$

2)

$\frac{7}{12}^{4} - \frac{3}{16}^{3} = \frac{28}{48} - \frac{9}{48} = \frac{19}{48}$

3)

$\frac{7}{16}^{3} - \frac{1}{6}^{8} = \frac{21}{48} - \frac{8}{48} = \frac{13}{48}$

4)

$1 - \frac{1}{3} = \frac{3}{3} - \frac{1}{3} = \frac{2}{3}$

Answer 2

To solve the given expressions, you need to perform the indicated operations. Let's go step by step:

1. $\frac{1}{2} - \frac{1}{4}$: To subtract fractions, you need a common denominator, which in this case is 4. So the expression becomes: $\frac{2}{4} - \frac{1}{4} = \frac{1}{4}$

2. $\frac{7}{12} - \frac{3}{16}$: The common denominator for these fractions is 48. So the expression becomes: $\frac{28}{48} - \frac{9}{48} = \frac{19}{48}$

3. $\frac{7}{16} - \frac{1}{6}$: To subtract these fractions, you need a common denominator, which is 48. So the expression becomes: $\frac{21}{48} - \frac{8}{48} = \frac{13}{48}$

4. $1 - \frac{1}{3}$: To subtract a whole number from a fraction, you convert the whole number into a fraction with the same denominator as the fraction. The expression becomes: $\frac{3}{3} - \frac{1}{3} = \frac{2}{3}$

Now, the final results of the expressions are:

1. $\frac{1}{2} - \frac{1}{4} = \frac{1}{4}$
2. $\frac{7}{12} - \frac{3}{16} = \frac{19}{48}$
3. $\frac{7}{16} - \frac{1}{6} = \frac{13}{48}$
4. $1 - \frac{1}{3} = \frac{2}{3}$