Question

-10(-4x+10)=-300 -10a+108=-64a 26-5m=2-9m -y+20=+y

Answer 1

-10(-4x+10)=-300

-40x-100=-300

-40x=-200

X=5

-10a+108=-64a

-10a+64a=-108

54a=-108

a=-2

26-5m=2-9m

-5m+9m=2-26

4m=-24

m=-6

-y+20=+y

-y-y=-20

-y^2=-20

y^2=20

y=2корень из 5

y=

Answer 2

Let's solve each equation step-by-step:

1. -10(-4x+10) = -300 Expand the expression inside the parentheses: 40x - 100 = -300 Add 100 to both sides to isolate the x term: 40x = -200 Divide both sides by 40 to solve for x: x = -200 / 40 x = -5

2. -10a + 108 = -64a Add 64a to both sides to isolate the a term: 54a + 108 = 0 Subtract 108 from both sides: 54a = -108 Divide both sides by 54 to solve for a: a = -108 / 54 a = -2

3. 26 - 5m = 2 - 9m Move the variables to one side and the constants to the other side: -5m + 9m = 2 - 26 4m = -24 Divide both sides by 4 to solve for m: m = -24 / 4 m = -6

4. -y + 20 = +y Add y to both sides to isolate the y term: 20 = 2y Divide both sides by 2 to solve for y: y = 20 / 2 y = 10

So, the solutions for each equation are:

1. x = -5
2. a = -2
3. m = -6
4. y = 10