Question

4x+7(x+5)<2+2-(6+3) Sos

Answer 1

$4x + 7(x + 5) < 2 + 2 - (6 + 3) \\ 4x + 7x + 35 < 4 - 6 - 3 \\ 11x < - 5 - 35 \\ 11x < - 40 \: \: \: \: \: \: | \div 11 \\ x < - \frac{40}{11} \\ x < - 3 \frac{7}{11}$

Answer 2

Ответ:

Пошаговое объяснение:

4x+7(x+5)<2+2-(6+3)

4х+7х+35<2+2-6-3

11х<-5-35

11х<-40

х<-40:11

х<-40/11

х< -3 7/11

Answer 3

To solve the inequality, let's first simplify both sides of the inequality step by step:

1. Simplify the left side: 4x + 7(x + 5)

Apply the distributive property (also known as the distributive law): 4x + 7x + 7 * 5

Combine like terms: 11x + 35

The inequality becomes: 11x + 35 < 2 + 2 - (6 + 3)

2. Simplify the right side: 2 + 2 - (6 + 3)

Perform operations inside parentheses first: 2 + 2 - 9

Perform addition and subtraction from left to right: 4 - 9

Now, the inequality becomes: 11x + 35 < -5

Now, to solve for x, isolate the variable on one side of the inequality. We want to get rid of the constant term 35, so we'll subtract 35 from both sides:

11x + 35 - 35 < -5 - 35

Simplify:

11x < -40

Finally, to solve for x, divide both sides by 11:

x < -40/11

So, the solution for the inequality is:

x < -40/11