Question

(11+2х)(16+2х) =300​

Answer 1

Ответ:

Пошаговое объяснение:

11*16+22x+32x+4x^2=300

4x^2+54x-124=0

D=2916+1984=4000

x1=(-54+70)/8=2

x2=(-50-70)/8=-15

Answer 2

.......вроде так. .......

Answer 3

To solve the equation (11+2x)(16+2x) = 300, we can expand the expression and then solve for x.

Expanding the equation: (11+2x)(16+2x) = 300 176 + 22x + 32x + 4x^2 = 300 4x^2 + 54x + 176 = 300

Rearranging the equation: 4x^2 + 54x + 176 - 300 = 0 4x^2 + 54x - 124 = 0

Now, we can solve this quadratic equation by factoring, completing the square, or using the quadratic formula. Let's use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

In our case, a = 4, b = 54, and c = -124. Substituting these values into the formula:

x = (-54 ± √(54^2 - 4 * 4 * -124)) / (2 * 4)

Simplifying further:

x = (-54 ± √(2916 + 1984)) / 8 x = (-54 ± √4900) / 8 x = (-54 ± 70) / 8

Now we have two possible solutions for x:

x1 = (-54 + 70) / 8 x1 = 16 / 8 x1 = 2

x2 = (-54 - 70) / 8 x2 = -124 / 8 x2 = -15.5

Therefore, the solutions to the equation (11+2x)(16+2x) = 300 are x = 2 and x = -15.5.