Question

(x+3)(x-2)-(x+4)(x-1)=6x решите уравнение ​

Answer 1

(x+3)(x-2)-(x+4)(x-1)=6x;

х²-2х+3х-6-х²+х-4х+4=6х;

-6+4= 6х+2х-3х-х+4х;

-2= 8х;

х= -2 ÷ 8;

х= - ¼.

ОТВЕТ: - ¼.

Answer 2

To solve the equation $(x+3)(x-2)-(x+4)(x-1) = 6x$, we first need to simplify the left-hand side and then find the value(s) of $x$ that satisfy the equation. Let's go step by step:

Step 1: Expand the expressions on the left-hand side: $(x+3)(x-2) = x^2 - 2x + 3x - 6 = x^2 + x - 6$ $(x+4)(x-1) = x^2 - x + 4x - 4 = x^2 + 3x - 4$

Step 2: Substitute the expanded expressions back into the original equation: $x^2 + x - 6 - (x^2 + 3x - 4) = 6x$

Step 3: Simplify the equation: $x^2 + x - 6 - x^2 - 3x + 4 = 6x$ Combine like terms: $x - 2 = 6x$

Step 4: Move all the $x$ terms to one side of the equation: $x - 6x = 2$ $-5x = 2$

Step 5: Isolate $x$ by dividing both sides by $-5$: $x = \frac{2}{-5}$

Step 6: Simplify the result: $x = -\frac{2}{5}$

So, the solution to the equation is $x = -\frac{2}{5}$.