Question

Tg(4x-п/4)=√3 ттттттт

Answer 1

$tg(4x-\frac{\pi}{4})=\sqrt3\\\\4x-\frac{\pi}{4}=\frac{\pi}{3}+\pi n\; ,\; n\in Z\\\\4x=\frac{7\pi}{12}+\pi n\; ,\; n\in Z\\\\x=\frac{7\pi }{48}+\frac{\pi n}{4}\; ,\; n\in Z$

Answer 2

The given equation is: Tg(4x - п/4) = √3

To solve this equation, let's isolate the tangent term by taking the tangent inverse (arctan) on both sides:

arctan(Tg(4x - п/4)) = arctan(√3)

Since the tangent and arctangent functions are inverses of each other, they cancel out, leaving us with:

4x - п/4 = arctan(√3)

Now, we can solve for x. Let's isolate x by adding п/4 to both sides of the equation:

4x = arctan(√3) + п/4

Finally, divide both sides by 4 to solve for x:

x = (arctan(√3) + п/4) / 4

This is the solution for x in terms of arctan and п/4.