Question

7x^2-4x+3=0 pleasseeee​

Answer 1

Ответ:

Уравнение не имеет корней в области действительных чисел x∉R

Пошаговое объяснение:

$7x^2-4x+3=0\\D=16-4*7*3=-68$

Так как D<0, уравнение не имеет корней в области действительных чисел x∉R

Answer 2

To solve the quadratic equation 7x^2 - 4x + 3 = 0, you can use the quadratic formula. The quadratic formula is given by:

x = (-b ± √(b^2 - 4ac)) / 2a

where: a = coefficient of x^2 term (7 in this case) b = coefficient of x term (-4 in this case) c = constant term (3 in this case) ± represents both the positive and negative roots of the equation.

Now, let's plug in the values and solve for x:

a = 7, b = -4, c = 3

x = (4 ± √((-4)^2 - 4 * 7 * 3)) / 2 * 7 x = (4 ± √(16 - 84)) / 14 x = (4 ± √(-68)) / 14

Since we have a negative value inside the square root (√(-68)), the equation has complex roots. The solutions for x will involve the imaginary unit "i."

x = (4 + √68i) / 14 x = (4 - √68i) / 14

Thus, the solutions to the equation are:

x = (4 + √68i) / 14 x = (4 - √68i) / 14

Please note that "i" represents the imaginary unit, where "i^2 = -1".