Question

2x^2+7x+3=0 plesssseee​

Answer 1

$2x^{2} +7x+3=0$

$D=b^{2} -4ac=49-24=25$

$x_{1} =-b+\sqrt{D} /2a=-7+5/4=-1/2$

$x_{2} =-b-\sqrt{D} /2a=-7-5/4=-3$

Ответ: -3; -1/2

Answer 2

To solve the quadratic equation 2x^2 + 7x + 3 = 0, we can use the quadratic formula. The quadratic formula is given by:

x = (-b ± √(b^2 - 4ac)) / 2a

Where a, b, and c are the coefficients of the quadratic equation ax^2 + bx + c = 0.

In your equation, a = 2, b = 7, and c = 3. Now, let's plug these values into the quadratic formula and find the solutions for x:

x = (-(7) ± √(7^2 - 4 * 2 * 3)) / 2 * 2 x = (-7 ± √(49 - 24)) / 4 x = (-7 ± √25) / 4 x = (-7 ± 5) / 4

Now, we'll find two possible solutions for x:

1. x = (-7 + 5) / 4 x = -2 / 4 x = -1/2

2. x = (-7 - 5) / 4 x = -12 / 4 x = -3

So, the solutions for the given quadratic equation are x = -1/2 and x = -3.