Question

8х^2-5х-3=0 пплииииззз​

Answer 1

Ответ:

x1 = 1; x2 = -3/8

Пошаговое объяснение:

D = b^2-4ac

D = (-5)^2-4*8*(-3) = 25+96 = 121

$\sqrt{D} = \sqrt{121} = 11$

x1 = (-b+$\sqrt{D}$)/2a = (5+11)/16 = 16/16 = 1

x2 = (-b-$\sqrt{D}$)/2a = (5-11)/16 = -6/16 = -3/8

Answer 2

$\displaystyle \tt 8x^{2} -5x-3=0$

$\displaystyle \tt D=b^{2}-4ac=(-5)^2-4*8*(-3)=121$

$\displaystyle \tt x=\frac{-b-\sqrt{D} }{2a}=\frac{5-11}{2*8}=-\frac{6}{16}=\bold-\frac{\bold3}{\bold8}$

$\displaystyle \tt x=\frac{-b+\sqrt{D} }{2a}=\frac{5+11}{2*8}=\frac{16}{16}=\bold\bold1$

Answer 3

To solve the quadratic equation 8x^2 - 5x - 3 = 0, we can use the quadratic formula. The quadratic formula is given by:

x = (-b ± √(b^2 - 4ac)) / 2a

where: a = coefficient of x^2 term = 8 b = coefficient of x term = -5 c = constant term = -3

Now, plug these values into the quadratic formula and solve for x:

x = (5 ± √((-5)^2 - 4 * 8 * (-3))) / 2 * 8

x = (5 ± √(25 + 96)) / 16

x = (5 ± √121) / 16

x = (5 ± 11) / 16

Now, we have two possible solutions:

1. x = (5 + 11) / 16 x = 16 / 16 x = 1

2. x = (5 - 11) / 16 x = -6 / 16 x = -3/8

So, the solutions to the quadratic equation are x = 1 and x = -3/8.