Question

5*(y-3)+27=4y+3*(2y-5)​

Answer 1

Ответ:

Пошаговое объяснение:

5×(у-3)+27=4у+3×(2у-5)

5у-15+27=4у+6у-15

5у+12=10у-15

5у-10у= -15-12

-5у= -27

5у=27

у=27÷5

у=5,4 или 5 2/5

Answer 2

Let's solve the given equation step-by-step:

5*(y - 3) + 27 = 4y + 3*(2y - 5)

Step 1: Distribute the multiplication on both sides of the equation.

5y - 15 + 27 = 4y + 6y - 15

Step 2: Combine like terms on both sides.

5y + 12 = 10y - 15

Step 3: Get all the terms containing "y" on one side and the constant terms on the other side. To do this, we'll move the term "5y" to the right side by subtracting 5y from both sides and move the constant term "12" to the left side by adding 15 to both sides.

5y - 5y + 12 = 10y - 5y - 15

12 = 5y - 15

Step 4: Isolate "y" on one side by moving the constant term to the right side.

12 + 15 = 5y

27 = 5y

Step 5: Solve for "y" by dividing both sides by 5.

y = 27 / 5

y = 5.4

So, the solution to the equation is y = 5.4.