Question

------------ /6x^2+4x-6=1

Answer 1

Ответ:

Пошаговое объяснение:

6x2 + 4x - 7 = 0

Найдем дискриминант квадратного уравнения:

D = b2 - 4ac = 42 - 4·6·(-7) = 16 + 168 = 184

Так как дискриминант больше нуля то, квадратное уравнение имеет два действительных корня:

$x = \frac{ -4 - \sqrt{184}}{2*6} = -\frac{1}{3} - \frac{1}{6}\sqrt{46}\\x = \frac{ -4 - \sqrt{184}}{2*6} = -\frac{1}{3} + \frac{1}{6}\sqrt{46}$

Answer 2

It seems like you've provided an equation: $\frac{6x^2 + 4x - 6}{1} = 1$. If you're looking to solve for $x$, I can guide you through the process.

First, let's simplify the equation by removing unnecessary components:

$6x^2 + 4x - 6 = 1$

Now, we want to isolate the variable $x$ on one side of the equation. Here's how you can solve for $x$:

Step 1: Subtract 1 from both sides of the equation:

$6x^2 + 4x - 6 - 1 = 0$ $6x^2 + 4x - 7 = 0$

Step 2: This is a quadratic equation in the form of $ax^2 + bx + c = 0$, where $a = 6$, $b = 4$, and $c = -7$. You can use the quadratic formula to find the solutions for $x$:

The quadratic formula is given by: $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

Plugging in the values: $x = \frac{-4 \pm \sqrt{4^2 - 4 \cdot 6 \cdot (-7)}}{2 \cdot 6}$

Simplify the expression under the square root: $x = \frac{-4 \pm \sqrt{16 + 168}}{12}$ $x = \frac{-4 \pm \sqrt{184}}{12}$

Step 3: Calculate the square root of 184: $\sqrt{184} \approx 13.56466$

Now we have two possible solutions for $x$: $x = \frac{-4 + 13.56466}{12} \approx 0.88039$ $x = \frac{-4 - 13.56466}{12} \approx -1.29603$

So, the solutions for the equation $\frac{6x^2 + 4x - 6}{1} = 1$ are approximately $x = 0.88039$ and $x = -1.29603$.