Question

X^2=12x-11 как решить?

Answer 1

Ответ:

на фотографии

Пошаговое объяснение:

на фотографии

Answer 2

X^2-12x+11=0
x^2-x-11x+11=0
x(x-1)-11(x-1)=0
(x-1)*(x-11)=0
x-1=0
x-11=0
x=1
x=11

Ответ: х1=1, х2=11

Answer 3

To solve the quadratic equation $x^2 = 12x - 11$, we need to bring all terms to one side and set the equation to zero. Then, we can use the quadratic formula to find the solutions for $x$.

Step 1: Rewrite the equation as a quadratic equation in standard form: $x^2 - 12x + 11 = 0$

Step 2: Now, we can use the quadratic formula, which states that for a quadratic equation of the form $ax^2 + bx + c = 0$, the solutions for $x$ are given by:

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

In our case, $a = 1$, $b = -12$, and $c = 11$. Plug these values into the quadratic formula:

$x = \frac{-(-12) \pm \sqrt{(-12)^2 - 4 \cdot 1 \cdot 11}}{2 \cdot 1}$

Simplify:

$x = \frac{12 \pm \sqrt{144 - 44}}{2}$

$x = \frac{12 \pm \sqrt{100}}{2}$

$x = \frac{12 \pm 10}{2}$

Now, we have two possible solutions for $x$:

1. When $x = \frac{12 + 10}{2} = \frac{22}{2} = 11$

2. When $x = \frac{12 - 10}{2} = \frac{2}{2} = 1$

So, the solutions to the equation $x^2 = 12x - 11$ are $x = 11$ and $x = 1$.