Question

5x - 3y =19{ 2x + y = 1​

Answer 1

у=1-2х

5х-3*(1-2х)=19

5х-3+6х=19

11х=19+3

11х=22

х=22/11

х=2

у=1-2*2

у=-3

ответ: (2;-3)

Answer 2

It looks like you've provided a system of two linear equations with two variables:

1. $5x - 3y = 19$
2. $2x + y = 1$

To solve for the values of $x$ and $y$, you can use various methods such as substitution or elimination. Let's use the elimination method here:

First, let's multiply the second equation by 3 so that the coefficients of $y$ in both equations will cancel each other out when added:

$3 \cdot (2x + y) = 3 \cdot 1$ $6x + 3y = 3$

Now, add this modified second equation to the first equation:

$5x - 3y + (6x + 3y) = 19 + 3$ $11x = 22$

Divide both sides by 11:

$x = 2$

Now that we have the value of $x$, substitute it back into the second equation to find $y$:

$2x + y = 1$ $2 \cdot 2 + y = 1$ $4 + y = 1$ $y = -3$

So, the solution to the system of equations is $x = 2$ and $y = -3$.