Question

1)1^-72)27^2/33)9×0.027^-1/3+(1/125)^-1/3​

Answer 1

Ответ:

не поняла ты какой класс

Answer 2

It looks like you've provided a series of mathematical expressions. Let's simplify each of them step by step:

1. $1^{-7} = 1$ (Any non-zero number raised to the power of 0 is 1.)

2. $27^2 = 729$ $3^3 = 27$ So, $27^2 = (3^3)^2 = 3^{3 \cdot 2} = 3^6$ Now, $\frac{27^2}{3^3} = 3^{6 - 3} = 3^3 = 27$

3. $9 \times 0.027^{-1/3} = 9 \times \frac{1}{\sqrt[3]{0.027}}$ $\sqrt[3]{0.027} = 0.3$, since $0.3^3 = 0.027$ So, $9 \times \frac{1}{0.3} = 9 \times 3 = 27$

4. $(1/125)^{-1/3}$ $\frac{1}{125}$ is equivalent to $125^{-1}$, because $125^{-1} = \frac{1}{125}$ $(125^{-1})^{-1/3} = 125^{1/3} = \sqrt[3]{125} = 5$

Now, let's add the simplified results together: $1 + 27 + 27 + 5 = 60$

So, the final result is 60.