Question

4cos4x + 1/2sinx/2. A(п/2;√2/2)

Answer 1

Ответ:

не знаю

Пошаговое объяснение:

посмотри на калькулятор

Answer 2

To find the value of the expression 4cos(4x) + 1/2sin(x/2) at point A(π/2, √2/2), we need to substitute the values of x and y into the expression.

At point A(π/2, √2/2), the x-coordinate is π/2, and the y-coordinate is √2/2.

Let's substitute these values into the expression:

4cos(4(π/2)) + 1/2sin(π/2/2)

Simplifying further:

4cos(2π) + 1/2sin(π/4)

Since the cosine function has a period of 2π, cos(2π) = cos(0) = 1.

So, the expression simplifies to:

4(1) + 1/2sin(π/4)

= 4 + 1/2(√2/2)

= 4 + √2/4

Therefore, the value of the expression 4cos(4x) + 1/2sin(x/2) at point A(π/2, √2/2) is 4 + √2/4.