Question

2х^2+4х-4=х^2+5х+(-3+х^2)​

Answer 1

Ответ:

Пошаговое объяснение:

2x^2+4x-4=x^2+ 5X+(-3+x^2)

2x^2+4x-4=2x^2+5x-3

4x-4=5x-3

4x-5x=-3+4

-x=1

x=-1

Answer 2

To solve the equation 2x^2 + 4x - 4 = x^2 + 5x + (-3 + x^2), you'll want to simplify and solve for x. Let's break down the steps:

1. Combine like terms on both sides of the equation: 2x^2 + 4x - 4 = x^2 + 5x - 3 + x^2

2. Group the x^2 terms and the x terms: 2x^2 + x^2 + 4x - 5x - 4 + 3 = 0

3. Combine the terms: 3x^2 - x - 1 = 0

Now you have a quadratic equation in standard form. To solve for x, you can use various methods, such as factoring, completing the square, or using the quadratic formula. Let's use the quadratic formula in this case:

The quadratic formula is: x = (-b ± √(b² - 4ac)) / 2a

In the equation 3x^2 - x - 1 = 0, a = 3, b = -1, and c = -1.

Calculate the discriminant (the value inside the square root): b² - 4ac = (-1)² - 4 * 3 * (-1) = 1 + 12 = 13

Now plug the values into the quadratic formula: x = (1 ± √13) / (2 * 3)

So, the solutions for x are: x = (1 + √13) / 6 x = (1 - √13) / 6

These are the approximate values of x. You can calculate their decimal equivalents if needed.