Question

(3m-2)2+3m(4-3m)=2m+3​

Answer 1

Ответ: m1 = 7/9, m2 = 1

Пошаговое объяснение:

6m - 4 +12m - 9m^2 = 2m+3

18m-4-9m^2=2m+3

18m-4-9m^2-2m-3=0

16m-7-9m^2=0

-16m+7+9m^2=0

9m^2-16m+7=0

9m^2-7m-9m+7=0

m(9m-7)-(9m-7)=0

(9m-7)(m-1)=0

9m-7=0

m-1=0

m=7/9

m=1

______________

m1 = 7/9, m2 = 1

Answer 2

To solve the equation (3m-2)^2 + 3m(4-3m) = 2m + 3, follow these steps:

1. Expand and simplify both sides of the equation:

   (3m-2)^2 + 3m(4-3m) = 2m + 3

   First, square (3m-2):

   9m^2 - 12m + 4 + 3m(4-3m) = 2m + 3

   Next, distribute 3m into the parentheses:

   9m^2 - 12m + 4 + 12m - 9m^2 = 2m + 3

   Notice that the terms "9m^2" and "-9m^2" cancel each other out:

   -12m + 4 + 12m = 2m + 3

2. Now, simplify further:

   -12m + 4 + 12m = 2m + 3

   The "12m" and "-12m" terms also cancel each other out:

   4 = 2m + 3

3. Isolate the "2m" term on one side by subtracting 3 from both sides of the equation:

   4 - 3 = 2m + 3 - 3

   1 = 2m

4. Finally, divide both sides by 2 to solve for m:

   1/2 = 2m/2

   1/2 = m

So, the solution to the equation is m = 1/2.