Question

1028. 1) (2x + 12 > 0.3x -9 < 0;2)5x - 25 <0,4.2 + 16 > 0:3)(1.1x + 1,16o.8x - 16 < 0.​

Answer 1

Ответ:

Пошаговое объяснение:

Х>-6;х<3. -6<х<3

2)х<5;х>-4 ; -4<х<5

3)х<2

В 3) непонятные условия

Answer 2

It appears you've provided a set of inequalities, and it seems you want to find the solution set for this system of inequalities. Let's solve them step by step:

1. $2x + 12 > 0.3x - 9$:

First, let's move all $x$ terms to the left side and constants to the right side:

$2x - 0.3x > -9 - 12$

$1.7x > -21$

Now, divide both sides by 1.7 (a positive number, so the inequality sign doesn't change):

$x > -21 / 1.7$

$x > -12.35$

So, the solution to the first inequality is $x > -12.35$.

2. $5x - 25 < 0$:

Add 25 to both sides:

$5x < 25$

Now, divide both sides by 5 (a positive number):

$x < 5$

The solution to the second inequality is $x < 5$.

3. $4.2 + 16 > 0.3$:

This inequality is always true because the left side is larger than the right side. So, it doesn't restrict the value of $x$.

4. $1.1x + 1 < 0.8x - 16$:

Let's move all $x$ terms to the left side and constants to the right side:

$1.1x - 0.8x < -16 - 1$

$0.3x < -17$

Now, divide both sides by 0.3 (a positive number):

$x < -17 / 0.3$

$x < -56.67$

So, the solution to the fourth inequality is $x < -56.67$.

Now, to find the combined solution for all these inequalities, we need to find the intersection of the solutions for each inequality. So, the overall solution is:

$x > -12.35$ (from the first inequality) and $x < 5$ (from the second inequality) and $x < -56.67$ (from the fourth inequality).

Since all three conditions must be satisfied simultaneously, we take the most restrictive condition, which is $x < -56.67$.

So, the solution to the system of inequalities is $x < -56.67$.