Question

4/40+u+16/40=31/40+6/40​

Answer 1

Ответ:

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Answer 2

To solve the equation:

(4/40) + u + (16/40) = (31/40) + (6/40)

First, simplify the fractions on both sides of the equation:

(1/10) + u + (4/10) = (31/40) + (3/10)

Now, find a common denominator for the fractions on each side, which is 10:

(1/10) + u + (4/10) = (31/40) + (12/40)

Now, add and subtract the fractions on both sides:

(1/10 + 4/10) + u = (31/40 + 12/40)

(5/10) + u = (43/40)

Now, simplify the fractions further:

(1/2) + u = (43/40)

Next, subtract 1/2 from both sides to isolate u:

u = (43/40) - (1/2)

To subtract these fractions, find a common denominator, which is 40:

u = (43/40) - (20/40)

Now, subtract the fractions:

u = (43 - 20) / 40

u = 23/40

So, the solution to the equation is:

u = 23/40