Question

6.22y -8 < 02y-3 > 0​

Answer 1

Ответ:

Пошаговое объяснение:

2у<8 2у<3=> у<3/2

у<4

Answer 2

Ответ:

2 × 3 - 8 < 0

2 × 2 - 3 > 0

Пошаговое объяснение:

............

Answer 3

To solve the inequality $6.22y - 8 < 0$ and $2y - 3 > 0$, we need to find the values of $y$ that satisfy both inequalities simultaneously.

Let's first solve the first inequality: $6.22y - 8 < 0$

Add 8 to both sides: $6.22y < 8$

Now, divide both sides by 6.22 (remember to reverse the inequality sign when dividing by a negative number): $y < \frac{8}{6.22}$

Now, let's solve the second inequality: $2y - 3 > 0$

Add 3 to both sides: $2y > 3$

Now, divide both sides by 2: $y > \frac{3}{2}$

So, we have the following two inequalities:

1. $y < \frac{8}{6.22}$
2. $y > \frac{3}{2}$

To find the values of $y$ that satisfy both inequalities, we need to find the intersection of the solution sets for each inequality.

The first inequality, $y < \frac{8}{6.22}$, gives us a range of values of $y$ that are less than approximately 1.29 (rounded to two decimal places).

The second inequality, $y > \frac{3}{2}$, gives us a range of values of $y$ that are greater than 1.5.

To satisfy both inequalities, $y$ must be both less than 1.29 and greater than 1.5 simultaneously, which is not possible. Therefore, there are no values of $y$ that satisfy both inequalities at the same time. The solution set is empty, indicating that there is no solution to this system of inequalities.