Question

9)(3x-y=6x + 3y = 6;​

Answer 1

Ответ:

 y=$1\frac{1}{3}$ x=5

Пошаговое объяснение:

3x-y=6         3*(6-3y)=6           y=$1\frac{1}{3}$

x+3y=6        x=6-3y                 x=5

3*(6-3y)=6

18-9y=6

-9y=6-18

-9y=-12    /(-9)

y=1$\frac{1}{3}$

Если я правильно поняла, то это система линейных уравнений.

Answer 2

It looks like you've provided a system of linear equations with two unknowns, $x$ and $y$:

1. $3x - y = 6$
2. $6x + 3y = 6$

To solve this system of equations, we can use either the substitution method, elimination method, or matrix methods like Gaussian elimination or Cramer's rule. Let's use the elimination method in this case.

First, let's manipulate the equations to eliminate one of the variables. Multiply the first equation by 3 to make the coefficients of $y$ in both equations equal:

1. $9x - 3y = 18$ (after multiplying the first equation by 3)
2. $6x + 3y = 6$

Now, we can add the equations to eliminate $y$:

$9x - 3y + 6x + 3y = 18 + 6$ $15x = 24$

Now, solve for $x$:

$x = \frac{24}{15} = \frac{8}{5}$

Next, substitute this value of $x$ into one of the original equations to solve for $y$. Let's use the first equation:

$3x - y = 6$ $3\left(\frac{8}{5}\right) - y = 6$ $y = \frac{8}{5} - \frac{18}{5} = -\frac{10}{5} = -2$

So, the solution to the system of equations is: $x = \frac{8}{5}$ $y = -2$