Question

(р - 6)(р² + 6р + 36)​

Answer 1

Ответ:

p³ - 216

Решение:

(р - 6)(р² + 6р + 36) = p³+6p²+36p-6p²-36p-216 =

= p³ - 216

Answer 2

To expand the expression (p - 6)(p² + 6p + 36), you can use the distributive property. Here's how you do it step by step:

(p - 6)(p² + 6p + 36)

1. First, distribute p to each term inside the second parentheses: p * p² + p * 6p + p * 36

This gives you:

p³ + 6p² + 36p

2. Next, distribute -6 to each term inside the second parentheses: -6 * p² - 6 * 6p - 6 * 36

This gives you:

-6p² - 36p - 216

Now, combine the two sets of terms:

p³ + 6p² + 36p - 6p² - 36p - 216

The 6p² and -6p² terms cancel out, and the 36p and -36p terms cancel out, leaving you with:

p³ - 216

So, the expanded expression is p³ - 216.