Question

(2x-2)^2(x-2)=(2x-2)(x-2)^2

Answer 1

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$\left(2x-2\right)^2\left(x-2\right)-\left(2x-2\right)\left(x-2\right)^2=0$

$2x\left(x-1\right)\left(x-2\right)=0$

$x=0\quad \mathrm{or}\quad \:x-1=0\quad \mathrm{or}\quad \:x-2=0$

ответь:

$x=0,\:x=1,\:x=2$

Answer 2

Решение на фото/////

Answer 3

To solve the equation $(2x - 2)^2(x - 2) = (2x - 2)(x - 2)^2$, you can start by simplifying both sides of the equation.

First, notice that both sides have a common factor of $(2x - 2)$. You can factor that out:

$(2x - 2)((2x - 2)(x - 2)) = (2x - 2)((x - 2)^2)$

Next, you can cancel out the common factor of $(2x - 2)$ on both sides:

$(2x - 2)(x - 2) = (x - 2)^2$

Now, you can expand both sides of the equation:

$2(x - 1)(x - 2) = (x - 2)(x - 2)$

Next, divide both sides of the equation by $(x - 2)$ because you know that $x$ cannot be equal to 2 (division by zero is undefined):

$2(x - 1) = x - 2$

Now, distribute the 2 on the left side:

$2x - 2 = x - 2$

Now, isolate $x$ on one side of the equation:

Subtract $x$ from both sides:

$2x - x - 2 = -2$

Simplify:

$x - 2 = -2$

Now, add 2 to both sides to solve for $x$:

$x = 0$

So, the solution to the equation is $x = 0$.