Question

3х – 5y=19,2х + Зу = 0;​

Answer 1

Ответ:

1) 3x-5y=19

3x-5y-19=19-19

3x-5y-19=0

2) 2x+3y=0

3y=-2x

3y:3=-2x:3

y=-2x:3

y=-2/3x

Пошаговое объяснение:

это дробь

Answer 2

It seems like you've provided a system of two linear equations:

1. 3x - 5y = 19
2. 2x + 3y = 0

You can solve this system of equations using various methods, such as substitution or elimination. I'll use the elimination method to solve for x and y.

First, let's multiply the second equation by 5 to make the coefficients of y in both equations cancel each other when added:

1. 3x - 5y = 19
2. 10x + 15y = 0

Now, you can add the two equations to eliminate y:

(3x - 5y) + (10x + 15y) = 19 + 0

This simplifies to:

13x = 19

Now, divide both sides by 13 to solve for x:

x = 19 / 13

x = 1.4615 (rounded to four decimal places)

Now that we have the value of x, you can substitute it into one of the original equations to solve for y. Let's use the first equation:

3x - 5y = 19

3(1.4615) - 5y = 19

4.3845 - 5y = 19

Now, subtract 4.3845 from both sides:

-5y = 19 - 4.3845

-5y = 14.6155

Finally, divide by -5 to solve for y:

y = 14.6155 / -5

y ≈ -2.9231 (rounded to four decimal places)

So, the solution to the system of equations is approximately:

x ≈ 1.4615 y ≈ -2.9231