Question

Тело движется прямолинейно по закону S(t) = 5^3 + 6^4 + 6, Найти скорость и ускорение точки в момент t=4 c.

Answer 1

Скорость это первая производная S(t), но формула в условии не зависит от t, по этому ( если не ошибся в условии) производная тогда равна 0. Аналогично, ускорение это первая произвoдная от скорости и ускорение равно 0

Answer 2

Finding Velocity and Acceleration of a Point at t=4

To find the velocity and acceleration of a point at time t=4, we can use the given position function S(t)=5^3 + 6^4 + 6.

Velocity at t=4

The velocity of the point at time t=4 can be found by taking the derivative of the position function S(t) with respect to time.

The derivative of S(t) with respect to t gives us the velocity function v(t).

The velocity v(t) at time t=4 can be calculated using the given position function S(t).

Velocity at t=4: The velocity of the point at t=4 is v(4)=... [[SOURCE #]].

Acceleration at t=4

The acceleration of the point at time t=4 can be found by taking the derivative of the velocity function v(t) with respect to time.

The derivative of v(t) with respect to t gives us the acceleration function a(t).

The acceleration a(t) at time t=4 can be calculated using the velocity function v(t).

Acceleration at t=4: The acceleration of the point at t=4 is a(4)=... [[SOURCE #]].

By using the given position function S(t)=5^3 + 6^4 + 6, we can calculate the velocity and acceleration of the point at time t=4.