Question

Поможіть обчислити вираз (x+3)(x2-3x+9) якщо x=-1/3

Answer 1

Ответ:

24 8/9

Пошаговое объяснение:

(-⅓+3)(-⅓*2-3*(-⅓)+9)

Answer 2

I can help you with your math problem. Here is the detailed solution:

To calculate the expression $(x+3)(x^2-3x+9)$ when $x=-\frac{1}{3}$, we need to substitute the value of $x$ into the expression and simplify it. We can use the distributive property to multiply the two factors. Here are the steps:

$(x+3)(x^2-3x+9)$

$= (x+3)(x^2)+ (x+3)(-3x)+ (x+3)(9)$

$= x^3+3x^2-3x^2-9x+9x+27$

$= x^3+27$

Now, we plug in $x=-\frac{1}{3}$ and simplify:

$x^3+27$

$= (-\frac{1}{3})^3+27$

$= -\frac{1}{27}+27$

$= \frac{26}{27}$

Therefore, the value of the expression $(x+3)(x^2-3x+9)$ when $x=-\frac{1}{3}$ is $\frac{26}{27}$. I hope this helps.Ответь+подробно.++Поможіть+обчислити+вираз+(x+3)(x2-3x+9)+якщо+x=-1/3+